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DPChallenge Forums >> General Discussion >> A couple math problems...
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 05/02/2006 01:44:17 PM · #1
I'm studying for the GMAT exam (to get into an MBA school), and I ran into two problems I'm having a real hard time solving. Any math geniuses in here? Please help! :)

//photos.imageevent.com/slo007/miscellaneous/miscphotos/Functions.jpg

//photos.imageevent.com/slo007/miscellaneous/miscphotos/Take-home-pay.jpg

Message edited by Konador - Please don't embed large images into the forums.
 05/02/2006 01:52:29 PM · #2
I make it (27 in a box) and 1/5.

Could well be wrong, though.
 05/02/2006 02:01:13 PM · #3
I got 27 for the first as well (9x6=54, hence m is even), but never was good at the second type...

edit; I concur on the 1/5 as well (didn't use an equation but took $100 as an example. At 1/5 she saved $20/mo, giving her $240 at year's end. She didn't save $80/month, which, x3, =$240)

Message edited by author 2006-05-02 14:05:09.
 05/02/2006 02:02:31 PM · #4
81, coz 9 is odd hence 9 becomes 27, 6 is even, it becomes 1/2 i.e 3 thefore 27x3= 81,
BTW i am also stuyding for GMAT
 05/02/2006 02:02:47 PM · #5
for the first one, simply calculate the "box function" for 9, 6 and all the answers. Then it becomes very simple to solve.


05/02/2006 02:10:31 PM · #6
Answer to the second should be 1/5th,
Lets suppose she saved a $ every month, hence in a year she saved 12a$.
Lets suppose she spent b$ every month.
Lets suppose her salary was C$,C= a+b, (saving +expense)per month.

as per statement , she saves 12a$ in one year. This is equal to 3 times what she did not take home i.e. b.
12a$=3b$ or 4a$=b$
C= a+b or c= 4a +a = 5a
a=c/5
05/02/2006 02:13:31 PM · #7
Originally posted by General:
81, coz 9 is odd hence 9 becomes 27, 6 is even, it becomes 1/2 i.e 3 thefore 27x3= 81,
BTW i am also stuyding for GMAT


Yes, but 81 in a box becomes 243, so the answer must be 27 in a box, surely.
 05/02/2006 02:14:02 PM · #8
You should pm laurielblack she's the Mathwiz of DPC!
 05/02/2006 02:14:23 PM · #9
Originally posted by AJAger:
I make it (27 in a box) and 1/5.

Could well be wrong, though.


I got the same answers.

For the 2nd one if x is the fraction saved, then (1-x) is the fraction not saved.

Frome the rest of the problem, you get 12x = 3(1-x)

Then, solving for x gives x=1/5
 05/02/2006 02:15:50 PM · #10
Now the second one. Yearly money saved is 3 times the monthly not saved. Knowing there are 12 months in a year, this leaves you with a simple algebra equation:

12x = 3y

or more simply:

4x = y

where x is the savings. they want to know the fraction of the total savings per month, which is x + y. Let's call that fraction z. We solve for it thus:

x = z(x + y)

so z= x / (x + y)

well, we can get rid of y since we know y = 4x, so

z = x/ (x + 4x)

which simplifies to

z = x/ 5x

and the x cancels out, leaving us with:

z = 1/5

Message edited by author 2006-05-02 14:17:05.
 05/02/2006 02:17:24 PM · #11
Originally posted by posthumous:
Now the second one. Yearly money saved is 3 times the monthly not saved. Knowing there are 12 months in a year, this leaves you with a simple algebra equation:

12x = 3y

or more simply:

4x = y

where x is the savings. they want to know the fraction of the total savings per month, which is x + y. Let's call that fraction z. We solve for it thus:

x = z(x + y)

so z= x / (x + y)

well, we can get rid of y since we know y = 4x, so

z = x/ (x + 4x)

which simplifies to

z = x/ 5x

and the x cancels out, leading us with:

z = 1/5


Do you teach math??
05/02/2006 02:19:12 PM · #12
Let pay = 100, and x=fraction saved

Then
100x * 12 = 3(100-(100x) .... fraction save per Yr = True condition

Solving

1200x = 300 - 300x
1200x + 300x = 300
1500x = 300
x = 300/1500
x = 1/5
05/02/2006 02:20:30 PM · #13
Originally posted by Spazmo99:
Do you teach math??

ha! no, just trying to help the OP really understand the problem instead of just solving it.
 05/02/2006 02:24:22 PM · #14
i agree with 81 for the first one

and after a few minutes of debate

1/5 for the second one

05/02/2006 02:24:41 PM · #15
Originally posted by posthumous:
Originally posted by Spazmo99:
Do you teach math??

ha! no, just trying to help the OP really understand the problem instead of just solving it.


Snap. Basically did same sum.... I jast had a few extra steps :)
 05/02/2006 02:28:46 PM · #16
Originally posted by posthumous:
ha! no, just trying to help the OP really understand the problem instead of just solving it.


Dumb question... what is "the OP"?

I've seen that phrase used repeatedly and keep hoping one day it will sink in. I give up. Tell me. :-)
05/02/2006 02:29:50 PM · #17
Originally posted by dwterry:


Dumb question... what is "the OP"?

I've seen that phrase used repeatedly and keep hoping one day it will sink in. I give up. Tell me. :-)


OP = Original Poster
 05/02/2006 02:34:49 PM · #18
Originally posted by Kaizer:
Originally posted by dwterry:


Dumb question... what is "the OP"?

I've seen that phrase used repeatedly and keep hoping one day it will sink in. I give up. Tell me. :-)


OP = Original Poster


WOOHOO, I can go home now!

We have a rule around here, you get to go home as soon as you learn something new. Sometimes you go home early. Sometimes you don't go home at all. (just kidding, of course, but it's one rule I wish we had!)
 05/02/2006 02:36:24 PM · #19
Originally posted by dwterry:

We have a rule around here, you get to go home as soon as you learn something new. Sometimes you go home early. Sometimes you don't go home at all. (just kidding, of course, but it's one rule I wish we had!)


I would like to enact a rule in which you can go home early if your cubicle mate is playing "I Will Always Love You" on the radio. I can't see how that wouldn't be supported.
 05/02/2006 02:39:38 PM · #20
Originally posted by posthumous:
Originally posted by Spazmo99:
Do you teach math??

ha! no, just trying to help the OP really understand the problem instead of just solving it.


OK, well, I was pretty confused by all the added variables. My math teacher used to do that too.
 05/02/2006 02:40:58 PM · #21
Originally posted by mk:
Originally posted by dwterry:

We have a rule around here, you get to go home as soon as you learn something new. Sometimes you go home early. Sometimes you don't go home at all. (just kidding, of course, but it's one rule I wish we had!)


I would like to enact a rule in which you can go home early if your cubicle mate is playing "I Will Always Love You" on the radio. I can't see how that wouldn't be supported.


I think that should result in immediate seizure and violent destruction of said radio, possibly using cubemate's head.
 05/02/2006 02:51:07 PM · #22
what?!?!?!? aren't those things like 4 foot by 4 foot?

that freakin' SUCKS! you should get to go home anyway.

Originally posted by mk:
cubicle mate
 05/02/2006 02:52:20 PM · #23
Ah, sorry. Bad wording. Cubicle wall mate? Person on the other side of the wall from me.

Although I did have an actual cubicle mate at my last job. It sucked a lot. We couldn't even both have our chairs pushed out at the same time.

Message edited by author 2006-05-02 14:52:27.
 05/02/2006 02:58:05 PM · #24
Originally posted by Spazmo99:
Originally posted by AJAger:
I make it (27 in a box) and 1/5.

Could well be wrong, though.


I got the same answers.

For the 2nd one if x is the fraction saved, then (1-x) is the fraction not saved.

Frome the rest of the problem, you get 12x = 3(1-x)

Then, solving for x gives x=1/5


Holy crap...I got those answers too. Are the planets in line??
05/02/2006 03:00:23 PM · #25
Originally posted by laurielblack:
Originally posted by Spazmo99:
Originally posted by AJAger:
I make it (27 in a box) and 1/5.

Could well be wrong, though.


I got the same answers.

For the 2nd one if x is the fraction saved, then (1-x) is the fraction not saved.

Frome the rest of the problem, you get 12x = 3(1-x)

Then, solving for x gives x=1/5


Holy crap...I got those answers too. Are the planets in line??


See, I got the same answers as the Math Queen, mine MUST be right.
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